TRADE DISCOUNT
Consumers buy goods from retailers, who in turn, purchase goods from wholesalers, manufactures or other retailers. Some wholesalers and manufactures issue catalogue describing the products sold by them. These catalogues also include the list prices (catalogue prices) of the products.
Retailers usually pay for the goods at prices lower than the list prices. The prices that the retailers pay after reduction in prices are called the net prices. The difference the list price and net price is called trade discount, that is
Trade discount = List price – Net price
A manufacturer normally quotes a discount rate in percentage to the retailer. The rate is called trade discount rate. The trade discount rate must be calculated on the list price.
Example:
If the list price of an article is RM500 and the trade discount is 20% then the amount of trade discount is RM500 X 20% = RM100
Hence the formula to calculate the amount of trade discount is given as
Amount of trade discount = List price X Trade discount rate
Example
The list price of a leather belt is RM180. A trade discount of 30% is offered. What is the net price of the belt?
List price = RM180
Trade discount = 30% X RM180
= RM54
Net price = List price – Trade discount
= RM180 – RM54
= RM126
FORMULA FOR FINDING THE NET PRICE
As an alternative to the method discussed above, the formula,
NP = L(1 – r)
can be used to find the net price. The derivation of the formula is discussed as follows
Let
Net price = NP
List price = L
Trade discount = r%
Net price = List price – Trade discount, we get
NP = L – Lr
= L (1 – r)
Example
Nur Kaelyn Elmira offers a discount of 32 ¼% on all jeans it sells. What is the net price of a pair of jeans that is listed at RM420?
Solution
List price = RM420
Trade discount = 32 ¼% X RM420
= RM135.45
Net price = List price – Trade discount
= RM420 – RM135.45
= RM284.55
Alternatively by using the formula, we get
NP = L (1 – r)
= 420 (1 – 32 ¼&)
= 420 (1 – 0.3225)
= RM284.55
Example
The net price of a camera with a 40% trade discount is RM480. What is the list price?.
Solution
Let the list price be RMX. Hence
Trade discount = 0.4X
Net price = List price – Trade discount
480 = X – 0.4X
480 = 0.6X
X = 480 ÷ 0.6
X = RM800
Hence the list price is RM800
Alternatively by using the formula, we get
NP = L (1 – r)
480 = L (1 – 40%)
= RM800
Example
A bill of RM1200 including prepaid handling charge of RM200 is offered a trade discount of 15%. What is the net price?
Trade discount = 0.15 X RM1000 = RM150
(It should be noted that the discount is based on the cost of goods, excluding any other costs)
Net price = (1000 – 150) + 200
= RM1050
Example
Nur Alesya Adriana sells an item for RM100 less 20% while Nur Harisya Adlina sells the sell item for RM120 less 40%
i. Find the net prices of the item for two shops
ii. What further discount percent must be offered by the shop that sells at a higher net price in order to meet the competitor’s price?
Solution
Nur Alesya Adriana : Net price = 100 (1 – 20%) = RM80
Nur Harisya Adlina : Net price = 100 (1 – 40%) = RM72
Nur Alesya Adriana sells at a higher net price. Let the additional discount percent be r%. Therefore
72 = 80 (1 – r)
= 28%
Nur Harisya Adlina must offer an additional 8% to meet its competitor’s price.
CHAIN DISCOUNT
Price of goods may go up or down within a period due to supply and demand situations. As such, multiple discounts are offered to the retailers on the same goods by the manufacturers or wholesalers. For instance, a wholesaler may offer trade discounts may offer trade discounts of 10%, 5% and 2%. Such multiple discounts are termed chain discount or series discount. In a chain discount, each discount rate is calculated on the successive net amount.
Example
A computer is advertised for RM4800 less 20% and 10%. Find
a. The net price
b. The total discount
Solution
List price = RM4800
Less 20% : 0.2 X RM4800 = RM960
= RM3840
Less 10% : 0.1 X RM3840 = RM384
Net price = RM3456
Total discount = RM4800 – RM3456
= RM1344
It should be noted that the chain discount of 20% and 10% is not the same as 30% since the 10% is based on the net amount (RM3840) after the first discount of 20% and not on the list price of RM4800. If a single discount of 30% is given in example 4, the net price is 70% of the list price, that is
Net price = 70% X RM4800
= RM3360
Thus, we see that chain discount of 20% and 10% is less than a single discount of 30%.
FORMULA FOR FINDING THE NET PRICE FOR A CHAIN DISCOUNT
When a chain discount is offered, the net price can be calculated more quickly by using the following formula.
For an item listed at L ringgit less r1%, r2% and r3% the net price, NP is given by
NP = L (1 – r1) (1 – r2) (1 – r3)
The formula is derived as follows
List price = L
Net price after first discount = L – Lr1
= L (1 – r1)
Net price after second discount = L (1 – r1) – L (1 – r1)r2
= L (1 – r1) (1 – r2)
Net price, NP = L (1 – r1) (1 – r2) – L (1 – r1) (1 – r2) r3
= L (1 – r1) (1 – r2) (1 – r3)
If there are two discount rates, r1 and r2 in the chain discount, the formula becomes
NP = L (1 – r1) (1 – r2)
Consider the following example.
Example
A television set with a catalogue price of RM2500 is offered a chain discount of 30%, 10% and 5%. Calculate the net price
Solution
From NP = L (1 – r1) (1 – r2) (1 – r3), we get
Net price = 2500 (1 – 30%) (1 – 10%) (1 – 5%)
= 2500 (0.7) (0.9) (0.95)
= RM1496.25
The net price can also be calculated in the following manner
List price = RM2500.00
Less 30% : 0.3 X RM2500 = RM750.00
= RM1750.00
Less 10% : 0.1 X RM1750 = RM175.00
= RM1575.00
Less 50% : 0.05 X RM1575 = RM78.78
Net price = RM1496.25
Example
A washing machine is advertised at RM2000 less 40%, 12% and 2 ½%. Find the net price.
Solution
From NP = L (1 – r1) (1 – r2) (1 – r3), we get
Net price = 2000 (1 – 40%) (1 – 12%) (1 – 2 ½%)
= 2000 (0.6) (0.88) (0.975)
= RM1029.60
Alternatively, the net price can be obtained as follows
List price = RM2000.00
Less 30% : 0.4 X RM2000 = RM800.00
= RM1200.00
Less 12% : 0.12 X RM1200 = RM144.00
= RM1056.00
Less 2 ½% : 0.025 X RM1056= RM26.40
Net price = RM1029.60
SINGLE DISCOUNT EQUIVALENT
A single discount equivalent is a single discount which is equivalent to a chain discount. The single discount equivalent, r for a chain discount of r1, r2 and r3 is given by
R = 1 – (1 – r1) (1 – r2) (1 – r3)
The formula is derived as follows
We have discuss that the net price of an item listed at RM L less r1, r2 and r3 is given as
NP = L (1 – r1) (1 – r2) (1 – r3)
Now let the single discount equivalent to the chain discount be r. Then
NP = L (1 – r)
Equating equations 1 and 2, we get
L (1 – r) = L (1 – r1) (1 – r2) (1 – r3)
Solving for r, we get
r = 1 – (1 – r1) (1 – r2) (1 – r3)
if there are two discount rates in the chain discount, then the above equation becomes r = 1 – (1 – r1) (1- r2).
Example
A product is advertised at RM1500 less 20%, 10% and 5%. Find
a. The single discount equivalent
b. The net price
Solution
a. From r = 1 – (1 – r1) (1 – r2) (1 – r3), we get
b. From NP = L(1 – r), we get
Net price = 1500 (1 – 31.6%)
= RM1026
Example
Find the single discount equivalent of 10% and 3%
Solution
From r = 1 – (1 –r1) (1 – r2), we get
r = 1 – (1 – 10%) (1 – 3%)
= 12.7%
CASH DISCOUNT
Wholesalers, manufactures and even retailers offer reduction on the amount due to customer s who pay their bills within a stipulated period of time. This is to encourage prompt payment of bills. The credit terms which comprise the cash discount rate and the credit period are usually shown in the invoice. If the bill is settled within the specified period, the buyer needs only to pay the net amount after deducting the cash discount from the amount in the invoice.
For example, a supplier may offer terms 3/10, net 20, which means that a 3% discount is given for payment within 10 days or the full amount is due in 20 days. If the buyer pays within 10 days from the date of the invoice, he is entitled to the 3% cash discount. This is the most common type of cash discount terms and is called ordinary dating. Other dating (which are not discussed here) include end-of-month dating, receipts of goods dating and extra dating.
Example
Explain the cash discount terms
a. 2/10, 1/30, n/60
b. Net 30
Solution
a. This term means 2% of the net price may be deducted if the invoice is paid within 10 days of the date of the invoice; 1% may be deducted if the invoice is paid between 11th and 30th day and the full amount must be paid by the 60th day. After the 60th day, the bill is overdue
b. Net 30 means payment is due within 30 days of the invoice date.
Example
An invoice dated 2 January 1995 for RM4010 was offered cash discount terms of 1/10, n/30. If the invoice was paid on 11 January 1995, what was the payment?
Solution
Since the invoice was paid 9 days after the date invoice (within the discount period) the buyer was entitled to a 1% cash discount
Cash discount = 0.01 X RM4010 = RM40.10
Payment = Invoice amount – Cash discount
= RM4010 – RM40.10
= RM3969.90
The payment was RM3969.90
Example
An invoice dated 10 April 1995 for RM2300 was offered cash discount terms of 3/10, 2/20, n/60. Find the payment if the invoice was paid on 28 April 1995.
Solution
Since the invoice was paid 18 days after the date invoice a cash discount of 2% was obtained. The buyer did not get the 3% cash discount as the invoice was not paid within the 3% discount period of 10 days.
Net payment = Net price – Cash discount
= RM2300 – 0.02 X RM2300
= RM2254
The payment was RM2254
Example
The total of an invoice with cash discount terms of 3/10, n/30 amounts to RM2090 which includes a prepaid freight charge of RM50. Find the amount that is needed to pay the invoice within the cash discount period.
Solution
Total amount including freight charge = RM2090.00
Freight charge = RM50.00
Cost of goods = RM2040.00
Cash discount = 3%(2040) = RM61.20
= RM1978.00
Freight charge = RM50.00
Amount to be paid = RM2028.80
BORROWING TO TAKE ADVANTAGE OF THE CASH DISCOUNT
Not many businesses have sufficient cash in hand to take advantage of the cash discount offered. Many of these companies borrow from banks on short term loans to take advantage of the offer
Consider the following example
Example
Anwar purchases some goods valued at RM2000 with a cash discount terms of 5/10, n/60. What will be the annualized cost of the credit if the cash discount is not taken?
Solution
Cash discount not taken = 5% X RM2000
= RM100
Credit period = 60 – 10 days
= 50 days
From the formula I =Prt, we get
100 = 1900 X r X 50 ÷ 360
r = 37.9%
Hence the annualized cost of credit is 37.9%
Alternatively, the following formula can be used
Annualised cost = Discount percent X 360
100 – Discount percent Credit period
= (5% ÷ 95%) X (360 ÷ 50)
= 37.9%
Example
On 20 May, Nur Irdina Darwisya purchased some goods invoiced at RM3000 with cash discount terms of 3/10, n/30. In order to pay the invoice on 30 May, she borrowed the money for 20 days at 9% per annum simple interest. How much did she save by borrowing to take advantage of the discount?
Solution
Cash discount = 3% X RM3000 = RM90
Principal borrowed = RM3000 – RM90 = RM2910
Credit period = 30 days - 10 days = 20 days
Interest incurred on the borrowing = Prt
= RM2910 X 0.09 X 20 ÷ 360
= RM14.55
Amount saved = Cash discount – Interest
= RM90 – RM14.55
= RM75.45
PARTIAL PAYMENT OF INVOICE
If a buyer pays only part of the invoice within the discount period, he receives a proportionate fraction of the cash discount that is offered. He will only receive the full amount of the cash discount if he settles all the payment.
Example
An invoice amounting to RM3000 and dated 15 July 2004 offered cash discount terms of 10/15, n/30. Find the amount outstanding if the buyer paid RM1000 on 20 July 2004.
Solution
Method 1
Cash discount offered = 10% X 3000 = RM300
The buyer paid RM1000 on 20 July 2004. Hence he was entitled to the cash discount offered. Since the RM1000 payment could not settle all the amount due, he was only entitled to a proportionate fraction of the cash discount offered. If he had made a payment of RM2700 (RM3000 – RM300), he would have received RM300 cash discount. Since he paid only RM1000, he was only entitled to cash discount of
(1000 ÷ 2700) X 300 = RM111.11
Hence, the amount outstanding = RM3000 – RM1111.11
= RM1888.89
Method 2
The following equation can also be used, that is
Amount paid = (credit given) X (1 – discount rate)
Since the amount paid was RM1000 and discount rate was 10%, then
1000 = (Credit given) X (1 X 10%)
Credit given = 1000 ÷ 90% = RM1111.11
Hence the amount outstanding = RM3000 – RM1111.11
= RM1888.89
TRADE AND CASH DISCOUNTS
More often than not, trade and cash discounts are offered simultaneously to a buyer. We shall discuss two examples where trade and cash discounts are offered at the same time.
Example
An invoice of RM10 000 and dated 18 April 2005 was offered 25% trade discount and cash discount terms of 9/10, n/30. Find
a. The trade discount offered
b. The cash discount offered
c. The net payment if the invoice was paid on 28 April 2005
Solution
Trade discount = 0.25 X 10000
= RM2500
Cash discount = 9% (10000 – 2500)
= RM675
Since the payment date fell within the cash discount period, he would get the 9% cash discount. Thus
Net payment = 10000 – (2500 + 675)
= RM6825
Example
An invoice of RM9000 dated 19 April 2005 was offered 13% trade discount and cash discount terms of 3/10, n/30. Find the net payment if the invoice was paid on 30 April 2005.
Solution
Trade discount = 0.13 X 9000
= RM1170
The buyer did not receive any cash discount since the last date to receive cash discount was 29 April 2005. He only received the trade discount. Thus,
Net payment = RM9000 – RM1170
= RM7830
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ReplyDeleteFACULTY OF BUSINESS AND ACCOUNTANCY
UNIVERSITI SELANGOR
ASSIGNMENT 1
COURSE : BUSINESS MATHEMATICS
COURSE CODE : PFD1123
LECTURER : MUZAIRIHANA BINTI MD MOID
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QUESTION Course Learning Outcome MARKS
Q1 CLO 2
Apply the principle of pricing in retail business.
/5
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DO NOT TURN THIS PAGE UNTIL YOU ARE TOLD TO DO SO
ANSWER ALL QUESTIONS.
QUESTION 1 (5 MARKS)
An invoice of RM 8,500 dated 20 July 2019 was offered 10% and 20% trade discount with cash discount terms of 5/10, 3/20, n/30.
a) Calculate the payment if it was settled on 25 July 2019.
(2 marks)
b) Find the outstanding balance if RM 3,000 was paid on 31 July 2019.
(2 marks)
c) Find the single discount rate that is equivalent to the series of trade discounts given.
(1 mark)
QUESTION 2 (5 MARKS)
A retailer received an invoice dated 20 April 2019 for RM 8,765. It was offered trade disconts of 15%, 5% and cash discounts of 3/15, 2/20, and n/60. If the payment was made two weeks after the date of invoice, find;
a) the single trade discount equivalent to the trade discount given.
(1 mark)
b) the amount of trade discount,
(2 marks)
c) the amount of payment.
(2 marks)
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ReplyDeleteA dealer receives an invoice from a wholesaler for the purchase of 100 shirts and 300 shorts.
ReplyDeleteThe invoice for 𝑅𝑀 1,000 (including a delivery cost of 𝑅𝑀60 and an insurance charge of
𝑅𝑀40) is dated 21 𝐽𝑢𝑙𝑦 2019. It offers trade discounts of 20 % and 12 % and cash discount
terms of 3/10, 2/20, 𝑛/60. The dealer pays the invoice on 1 𝐴𝑢𝑔𝑢𝑠𝑡 2019.
a) If the unit price of the shirts (before discount) is three times that of the shorts, calculate
the unit price of the shirts and shorts offered by the wholesaler. (4 marks)
b) The dealer wants a net profit of 10 % on the sale of all the shirts and shorts. If the
estimated operating expenses amount to 20 % of the cost, what is the expected revenue
from the sale of all the shirts and shorts? (3 marks)
c) Assume that sales are rather slow at the above selling prices. Therefore, he offers a
discount but still enjoys a gross profit of 20 % on cost. Determine the discount rate that
is offered. (3 marks)
can i get the answer
DeleteJamilah receives an invoice for the purchase of 40 batteries for 𝑅𝑀 8,440 on 31 𝑀𝑎𝑟𝑐ℎ 2020. Trade discounts are 5 % and 3 % and the cash discount terms are 8/10,5/30,𝑛/60. She pays the invoice on 19 𝐴𝑝𝑟𝑖𝑙 2020. She plans to sell the batteries by allowing 10 % of the cost for operating expenses and 28 % of the selling price for gross profit.
ReplyDeletea) Find the payment on 19 𝐴𝑝𝑟𝑖𝑙 2020. (3 marks)
b) Find the selling price and the net profit for each battery. (3 marks)
c) After two months, Jamilah manages to sell 30 batteries. The remaining 10 batteries are sold by allowing 10 % markdown. Calculate the total sales made by Jamilah if all the batteries are sold. (4 marks
what if the question [ the list price of an android is rm3000. After deducting a trade discound of 10% and y%, the net price is rm2565. Find the value of y
ReplyDelete